Gray Inc. is a software fabricant specialized in management of Gray codes. An n-binary code, for n ≥ 1, is a sequence of words w0,w1,... that includes every possible binary word of n bits. An n-Gray code is an n-binary code such that between any two consecutive words there is only one bit that changes, i.e., they differ at exactly one position. As you might be aware by now, there are many n-Gray codes. Gray Inc. produces its own particular kind of Gray code in the following way (name Gn the produced n-Gray code, n ≥ 1): ⟨0, 1⟩ if n = 1 Gn = (0Gn−1) (1GRn−1) if n ≥ 2 The notation defining Gn should be understood as follows: • bA : appends bit b to every element of the sequence A; • AB : concatenates sequences A and B; • AR : sequence with the elements of sequence A in reversed order. For instance, and (0G1)(1GR1 ) G2 = = (0⟨0, 1⟩) (1⟨0, 1⟩R ) = (0⟨0, 1⟩) (1⟨1, 0⟩) = ⟨00, 01⟩⟨11, 10⟩ = ⟨00, 01, 11, 10⟩ (0G2)(1GR2 ) G3 = = (0⟨00, 01, 11, 10⟩) (1⟨00, 01, 11, 10⟩R ) = (0⟨00, 01, 11, 10⟩) (1⟨10, 11, 01, 00⟩) = ⟨000, 001, 011, 010⟩⟨110, 111, 101, 100⟩ = ⟨000, 001, 011, 010, 110, 111, 101, 100⟩ Observe that not only Gn is an n-Gray code, but also a circular Gray code as the first word in the sequence may be regarded as the successor of the last one in the sequence. Gray Inc. wants your help to solve the following problem: given a binary word w in Gn and a natural number m, they want to produce the binary word in the sequence Gn that is m words ahead w in the listing (of course, considering the circular ordering described above). Can you help them? Input The problem input consists of several cases, each one defined by a line with an integer m (0 < m ≤ 1000), and a binary n-word w (1 ≤ n ≤ 100), separated by one blank. The end of the input is given by a line with m = 0 and w = 0. Output For each input case, your solution should output the n-binary word that is m words ahead of w in the listing of Gn.
2/2 Sample Input 10 30 11 1 11 6 011 123 010101010 00 Sample Output 1 1 0 10 000 111100100